# Point-Slope Form

How to write and graph a linear equation in point-slope form: formula, 3 examples, and their solutions.

## Formula

The linear equation in point-slope form is

y = m(x - x_{1}) + y_{1}.

m: Slope of the line

(x_{1}, y_{1}): Point on the line

## ExampleSlope: 3, (1, 2)

The slope is 2.

And the point on the line is (1, 2).

Then the linear equation

in point-slope form is

y = 3(x - 1) + 2.

Change the linear equation to slope-intercept form.

Then y = 3x - 1

So

y = 3x - 1

is the answer.

This is the graph of the linear equation

y = 3(x - 1) + 2.

The slope is 3.

And the line passes through (1, 2).

## ExampleGraph y = -2(x + 4) + 1

To see the point part clearly,

change +4 to -(-4).

Then y = -2(x - (-4)) + 1.

This is in point-slope form.

The slope is -2.

And the line passes through (-4, 1).

See y = -2(x - (-4)) + 1.

The line passes through (-4, 1).

So draw the point (-4, 1)

on the coordinate plane.

See y = -2(x - (-4)) + 1 again.

The slope is -2. (= -2/1)

So move 1 unit to the right

and move 2 units downward.

Mark this endpoint.

Draw a line that passes through

(-4, 1) and the marked endpoint.

This is the graph of the linear equation

y = -2(x + 4) + 1.

## Example(2, 1), (5, 4)

The slope is not given.

So, from the given points (2, 1) and (5, 4),

find the slope of the line.

Draw a line that passes through (2, 1) and (5, 4).

Find the slope of the line.

The change of x is 5 - 2 = 3.

The change of y is 4 - 1 = 3.

So the slope is

m = 3/3 = 1.

The slope of the line is 1.

And the line passes through (2, 1).

Then the linear equation

in point-slope form is

y = 1(x - 2) + 1.

You can also use the other point (5, 4).

You'll get the same answer.

Write the linear equation

in slope-intercept form.

Then y = x - 1.

So

y = x - 1

is the answer.